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=-0.4Y^2+2.3Y+2
We move all terms to the left:
-(-0.4Y^2+2.3Y+2)=0
We get rid of parentheses
0.4Y^2-2.3Y-2=0
a = 0.4; b = -2.3; c = -2;
Δ = b2-4ac
Δ = -2.32-4·0.4·(-2)
Δ = 8.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.3)-\sqrt{8.49}}{2*0.4}=\frac{2.3-\sqrt{8.49}}{0.8} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.3)+\sqrt{8.49}}{2*0.4}=\frac{2.3+\sqrt{8.49}}{0.8} $
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